Circle touching both axes and radius 5 is
WebThe given radius of the circle is 5 units, i.e. a = 5. Thus, the equation of the circle is x 2 + y 2 + 10 x + 10 y + 25 = 0. Case IV: If the circle lies in the fourth quadrant: The equation of a … WebThe equation of the circle which touches the axes of coordinates and the line 3x+ 4y=1 and whose centre lies in the first quadrant is x 2+y 2−2cx−2cy+c 2= 0, where c is. This question has multiple correct options.
Circle touching both axes and radius 5 is
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WebEquation of a Circle Touching Both Axes. In this tutorial we find the equation of circles with both axes touching, i.e. the X-axis and Y-axis, with any given radius. So we will find the …
WebFinding the equation of circle, Given the radius of the circle is a and the circle touches both the axis. Visualizing the given information: We see that the coordinates of the … WebThe circle touches the horizontal axis at a particular point in a special case and it can be written mathematically in an equation. Let C represents the centre of a circle and P …
WebJul 25, 2016 · Explanation: If the radius is a, the center of the circle will be at ( ± a, ± a). The four pairs of signs is indicative of the quadrant in which the circle lies.. So, the equation is f (x,y,a) = (x ± a)2 +(y ± a)2 − a2 = x2 +y2 ± 2ax ± 2ay + a2 = 0. 'a' is the parameter. for this family of circles f (x, y, a) = 0.. Answer link WebThe equation of a circle that touches both the coordinate axes and has radius a is x 2 + y 2 − 2 a x + 2 a y + a 2 = 0. The given radius of the circle is 5 units, i.e. a = 5. Thus, the equation of the circle is x 2 + y 2 − 10 x + 10 y + 25 = 0. Hence, the required equation of the circle is x 2 + y 2 ± 10x ± 10y + 25 = 0.
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WebFind the equation of a circle which touches both the axes and the line 3x−4y+8=0 and lies in the third quadrant. A x 2+y 2+4x+4y−4=0 B x 2+y 2−4x−4y+4=0 C x 2+y 2+4x+4y+4=0 … how to stop recurring credit card paymentsWebJul 25, 2016 · The family of circles touching both the axes in any of the four quadrants is given by f(x, y, a) = x^2+y^2+-2ax+-2ay+a^2=0. If the radius is a, the center of the circle … how to stop recurring invoices in quickbooksWebFind the equation of the circle which touches the both axes in first quadrant and whose radius is a A x 2+y 2−2ax−2ay+a 2=0 B x 2+y 2−2ax+2ay−a 2=0 C x 2+y 2+2ax−2ay+a 2=0 D none of the above Medium Solution Verified by Toppr Correct option is A) Given, ⇒ circle of radius a touches both axis in 1 st quadrant so its centre will be (a,a). how to stop recurring credit card chargesWebFeb 12, 2024 · The equation of circle touching the coordinate axes is (x - a) 2 + (y - a) 2 = a 2, When the circle touches both x-axis and y-axis i.e., h = k = a. (x - a) 2 + (y - a) 2 = … read hunt insuranceWebThe number of circles touching both the axes with radius 5 is 1) 4 2) 3 3) 2 4) 0 correct answer is option '1'. can you explain this answer ? Most Upvoted Answer The number of circles touching both the axes with radius 5 is 1) 4 2) ... As there are four quadrants there exist 4 circles touching both the axes with radius 5 View all answers read humidityWebApr 2, 2024 · Given that circle lies in the First Quadrant and touches both the axes of coordinates. $ \therefore h = k = 2 $ The equation of the circle formed with Radius $ 2 $ units and value of $ h,k = 2 $ is $ {(x - 2)^2} + {(y - 2)^2} = {2^2}.....(1) $ Now, Let the radius of the required circle be $ R $ . $ \therefore $ Equation of Circle with ... read hundred dresses onlineWebMar 30, 2024 · Ex 11.1, 12 (Method 1) Find the equation of the circle with radius 5 whose centre lies on x-axis and passes through the point (2, 3). We know that equation of … how to stop recurring payments from bank